vector_math: Return by const reference for const operator[]

Makes behavior between both overloads consistent.
This commit is contained in:
Lioncash 2017-12-03 19:23:56 -05:00
parent e23c3cd7f7
commit cc2ff226ae

View file

@ -131,7 +131,7 @@ public:
{
return *((&x) + i);
}
T operator[](const int i) const {
const T& operator[](const int i) const {
return *((&x) + i);
}
@ -288,7 +288,7 @@ public:
{
return *((&x) + i);
}
T operator[](const int i) const {
const T& operator[](const int i) const {
return *((&x) + i);
}
@ -502,7 +502,7 @@ public:
{
return *((&x) + i);
}
T operator[](const int i) const {
const T& operator[](const int i) const {
return *((&x) + i);
}