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glasm: Ensure reg alloc order across compilers on GLASM

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Use a struct constructor to serialize register allocation arguments to
ensure registers are allocated in the same order regardless of the
compiler used.

The A and B functions can be called in any order when passed as
arguments to "foo":

  foo(A(), B())

But the order is guaranteed for curly-braced constructor calls in
classes:

  Foo{A(), B()}

Use this to get consistent behavior.
This commit is contained in:
ReinUsesLisp 2021-05-10 19:32:10 -03:00 committed by ameerj
parent c917290497
commit 8c81a20ace
1 changed files with 14 additions and 11 deletions
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15
src/shader_recompiler/backend/glasm/emit_glasm.cpp
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@ -128,24 +128,27 @@ auto Arg(EmitContext& ctx, const IR::Value& arg) {
}
}
template <auto func, bool is_first_arg_inst, typename... Args>
void InvokeCall(EmitContext& ctx, IR::Inst* inst, Args&&... args) {
template <auto func, bool is_first_arg_inst>
struct InvokeCall {
template <typename... Args>
InvokeCall(EmitContext& ctx, IR::Inst* inst, Args&&... args) {
if constexpr (is_first_arg_inst) {
func(ctx, *inst, args.Extract()...);
} else {
func(ctx, args.Extract()...);
}
}
};
template <auto func, bool is_first_arg_inst, size_t... I>
void Invoke(EmitContext& ctx, IR::Inst* inst, std::index_sequence<I...>) {
using Traits = FuncTraits<decltype(func)>;
if constexpr (is_first_arg_inst) {
InvokeCall<func, is_first_arg_inst>(
ctx, inst, Arg<typename Traits::template ArgType<I + 2>>(ctx, inst->Arg(I))...);
InvokeCall<func, is_first_arg_inst>{
ctx, inst, Arg<typename Traits::template ArgType<I + 2>>(ctx, inst->Arg(I))...};
} else {
InvokeCall<func, is_first_arg_inst>(
ctx, inst, Arg<typename Traits::template ArgType<I + 1>>(ctx, inst->Arg(I))...);
InvokeCall<func, is_first_arg_inst>{
ctx, inst, Arg<typename Traits::template ArgType<I + 1>>(ctx, inst->Arg(I))...};
}
}