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Use a "branchmap" call to identify remote branches in "arc-hg"
Summary: Ref T9948. Ref T13546. To identify remote branch heads -- not just modified heads -- use "branchmap" like "hg outgoing" does. I wasn't able to find any other way to get what we want: for example, with a bundlerepo, "peer.heads()" and "peer.changelog.heads()" include local branches which are not present in the remote. It generally seems difficult (perhaps impossible?) to distinguish between these cases by using "getremotechanges()": - branch X exists at position Y in both the local and remote; - branch X exists at positino Y in the local, but not the remote. In any case, this seems to work properly and //should// do less work than "getremotechanges()" since we don't need to pull as much data over the wire. Test Plan: Ran "hg arc-ls-markers" in various repositories, got what appeared to be a faithful representation of the remote branch and bookmark state. Maniphest Tasks: T13546, T9948 Differential Revision: https://secure.phabricator.com/D21349
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1 changed files with 7 additions and 12 deletions
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@ -159,25 +159,20 @@ def remotemarkers(ui, repo, source, opts):
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source, branches = hg.parseurl(ui.expandpath(source))
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remote = hg.peer(repo, opts, source)
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bundle, remotebranches, cleanup = bundlerepo.getremotechanges(
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ui,
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repo,
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remote)
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with remote.commandexecutor() as e:
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branchmap = e.callcommand('branchmap', {}).result()
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try:
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for n in remotebranches:
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ctx = bundle[n]
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for branch_name in branchmap:
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for branch_node in branchmap[branch_name]:
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markers.append({
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'type': 'branch',
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'name': ctx.branch(),
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'node': node.hex(ctx.node()),
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'name': branch_name,
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'node': node.hex(branch_node),
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})
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finally:
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cleanup()
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with remote.commandexecutor() as e:
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remotemarks = bookmarks.unhexlifybookmarks(e.callcommand('listkeys', {
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'namespace': 'bookmarks',
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'namespace': 'bookmarks',
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}).result())
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for mark in remotemarks:
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